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(F)=-6F^2+12F+21
We move all terms to the left:
(F)-(-6F^2+12F+21)=0
We get rid of parentheses
6F^2-12F+F-21=0
We add all the numbers together, and all the variables
6F^2-11F-21=0
a = 6; b = -11; c = -21;
Δ = b2-4ac
Δ = -112-4·6·(-21)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-25}{2*6}=\frac{-14}{12} =-1+1/6 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+25}{2*6}=\frac{36}{12} =3 $
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